What is the critical angle for light traveling from glass (n = 1.5) to air (n =

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Question: What is the critical angle for light traveling from glass (n = 1.5) to air (n = 1)? (2019)

Options:

Correct Answer: 41.8 degrees

Exam Year: 2019

Solution:

Using the formula sin(c) = n2/n1, we find sin(c) = 1/1.5, thus c = sin^(-1)(2/3) ≈ 41.8 degrees.

What is the critical angle for light traveling from glass (n = 1.5) to air (n = 1)? (2019)

What is the critical angle for light traveling from glass (n = 1.5) to air (n = 1)? (2019)

Step 1: Identify the refractive indices. For glass, n1 = 1.5 and for air, n2 = 1.
Step 2: Use the formula for critical angle: sin(c) = n2 / n1.
Step 3: Substitute the values into the formula: sin(c) = 1 / 1.5.
Step 4: Calculate 1 / 1.5, which equals approximately 0.6667.
Step 5: To find the critical angle c, use the inverse sine function: c = sin^(-1)(0.6667).
Step 6: Calculate sin^(-1)(0.6667) to find the angle in degrees, which is approximately 41.8 degrees.

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