An object is thrown vertically upwards with a speed of 20 m/s. How high will it

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Question: An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)

Options:

Correct Answer: 40 m

Exam Year: 2020

Solution:

Using the formula h = (u²)/(2g) = (20²)/(2 × 10) = 20 m.

An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)

An object is thrown vertically upwards with a speed of 20 m/s. How high will it rise before coming to rest? (Take g = 10 m/s²) (2020)

Step 1: Identify the initial speed (u) of the object, which is given as 20 m/s.
Step 2: Identify the acceleration due to gravity (g), which is given as 10 m/s².
Step 3: Use the formula for maximum height (h) when an object is thrown upwards: h = (u²) / (2g).
Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 × 10 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 × 10 m/s², which equals 20 m/s².
Step 7: Divide 400 m²/s² by 20 m/s² to find h: h = 400 / 20 = 20 m.
Step 8: Conclude that the maximum height the object will rise is 20 meters.

Kinematics – The question tests the understanding of kinematic equations, specifically the relationship between initial velocity, acceleration due to gravity, and maximum height in vertical motion.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the peak of the object's trajectory.