A 5 kg block of metal is heated from 20°C to 100°C. If the specific heat capacity of the metal is 0.5 J/g°C, how much heat is required? (2023)

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Q: A 5 kg block of metal is heated from 20°C to 100°C. If the specific heat capacity of the metal is 0.5 J/g°C, how much heat is required? (2023)

Solution: Heat (Q) = m * c * ΔT = 5000 g * 0.5 J/g°C * (100°C - 20°C) = 5000 * 0.5 * 80 = 200000 J = 2000 J.

Steps: 9

Step 1: Identify the mass of the metal block. The mass is given as 5 kg.
Step 2: Convert the mass from kilograms to grams. Since 1 kg = 1000 g, 5 kg = 5000 g.
Step 3: Identify the specific heat capacity of the metal. It is given as 0.5 J/g°C.
Step 4: Determine the initial and final temperatures. The initial temperature is 20°C and the final temperature is 100°C.
Step 5: Calculate the change in temperature (ΔT). ΔT = final temperature - initial temperature = 100°C - 20°C = 80°C.
Step 6: Use the formula for heat (Q): Q = m * c * ΔT, where m is mass, c is specific heat capacity, and ΔT is the change in temperature.
Step 7: Substitute the values into the formula: Q = 5000 g * 0.5 J/g°C * 80°C.
Step 8: Calculate the heat required: Q = 5000 * 0.5 * 80 = 200000 J.
Step 9: Convert the heat from joules to kilojoules if needed. Here, 200000 J = 200 kJ.