What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at
Practice Questions
Q1
What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 2400 J of heat? (2022)
30 J/g
40 J/g
50 J/g
60 J/g
Questions & Step-by-Step Solutions
What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 2400 J of heat? (2022)
Step 1: Understand the problem. We need to find the latent heat of fusion of ice, which is the amount of heat required to melt ice without changing its temperature.
Step 2: Identify the given values. We have 80 grams of ice (m) and the heat absorbed (Q) is 2400 Joules.
Step 3: Use the formula for latent heat of fusion: L = Q / m, where L is the latent heat of fusion, Q is the heat absorbed, and m is the mass of the ice.
Step 4: Plug in the values into the formula: L = 2400 J / 80 g.
Step 5: Calculate the result: L = 30 J/g.
Step 6: Conclude that the latent heat of fusion of ice is 30 J/g.
