In a parallel circuit with two resistors of 6 ohms and 3 ohms, what is the total

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Question: In a parallel circuit with two resistors of 6 ohms and 3 ohms, what is the total resistance?

Options:

Correct Answer: 2 ohms

Solution:

The total resistance in parallel is given by 1/R_total = 1/R1 + 1/R2. Thus, 1/R_total = 1/6 + 1/3 = 1/2, so R_total = 2 ohms.

In a parallel circuit with two resistors of 6 ohms and 3 ohms, what is the total resistance?

In a parallel circuit with two resistors of 6 ohms and 3 ohms, what is the total resistance?

Step 1: Identify the resistors in the parallel circuit. We have R1 = 6 ohms and R2 = 3 ohms.
Step 2: Write the formula for total resistance in a parallel circuit: 1/R_total = 1/R1 + 1/R2.
Step 3: Substitute the values of R1 and R2 into the formula: 1/R_total = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
Step 5: Rewrite 1/3 as 2/6 so that both fractions have the same denominator: 1/R_total = 1/6 + 2/6.
Step 6: Add the fractions: 1/R_total = (1 + 2)/6 = 3/6.
Step 7: Simplify 3/6 to 1/2: 1/R_total = 1/2.
Step 8: To find R_total, take the reciprocal of 1/2: R_total = 2 ohms.

Parallel Circuit Resistance – Understanding how to calculate total resistance in a parallel circuit using the formula 1/R_total = 1/R1 + 1/R2.