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What is the value of (x + 1)^5 when x = 2?

Practice Questions

1 question
Q1
What is the value of (x + 1)^5 when x = 2?
  1. 32
  2. 64
  3. 128
  4. 256

Questions & Step-by-step Solutions

1 item
Q
Q: What is the value of (x + 1)^5 when x = 2?
Solution: Using the binomial theorem, (x + 1)^5 = C(5,0)(2)^5 + C(5,1)(2)^4 + C(5,2)(2)^3 + C(5,3)(2)^2 + C(5,4)(2)^1 + C(5,5)(2)^0 = 32 + 80 + 80 + 40 + 10 + 1 = 243.
Steps: 0

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