What is the equilibrium constant (K) for the dissociation of acetic acid (CH3COO

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Question: What is the equilibrium constant (K) for the dissociation of acetic acid (CH3COOH) in water? (2023)

Options:

Correct Answer: 1.8 x 10^-5

Exam Year: 2023

Solution:

The dissociation constant (K) for acetic acid is approximately 1.8 x 10^-5, indicating it is a weak acid.

What is the equilibrium constant (K) for the dissociation of acetic acid (CH3COOH) in water? (2023)

What is the equilibrium constant (K) for the dissociation of acetic acid (CH3COOH) in water? (2023)

Step 1: Understand that acetic acid (CH3COOH) is a weak acid that partially dissociates in water.
Step 2: Write the dissociation equation for acetic acid: CH3COOH ⇌ CH3COO- + H+.
Step 3: Recognize that the equilibrium constant (K) is a measure of the extent of dissociation of the acid.
Step 4: The formula for the equilibrium constant (K) for this reaction is K = [CH3COO-][H+]/[CH3COOH].
Step 5: Know that for acetic acid, the value of K is approximately 1.8 x 10^-5, which indicates it does not dissociate completely.

No concepts available.