In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the

In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2023)

In the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what will happen if the volume of the container is increased? (2023)

Step 1: Identify the reaction: 2SO2(g) + O2(g) ⇌ 2SO3(g).
Step 2: Count the number of gas moles on each side of the reaction.
Step 3: On the left side, there are 2 moles of SO2 and 1 mole of O2, totaling 3 moles.
Step 4: On the right side, there are 2 moles of SO3, totaling 2 moles.
Step 5: Understand that increasing the volume of the container decreases the pressure inside.
Step 6: According to Le Chatelier's principle, the system will try to counteract the change (decrease in pressure) by shifting the equilibrium.
Step 7: The equilibrium will shift towards the side with more moles of gas, which is the left side (3 moles) in this case.

No concepts available.