What is the force between two charges of +1 µC and +1 µC separated by 1 m?

1 question

1 item

Q: What is the force between two charges of +1 µC and +1 µC separated by 1 m?

Solution: F = k * |q1 * q2| / r^2 = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (1 m)² = 8.99 N.

Steps: 9

Step 1: Identify the values given in the problem. We have two charges, q1 = +1 µC and q2 = +1 µC, and the distance r = 1 m.
Step 2: Convert the charges from microcoulombs (µC) to coulombs (C). 1 µC = 1 x 10^-6 C, so q1 = 1 x 10^-6 C and q2 = 1 x 10^-6 C.
Step 3: Use Coulomb's Law formula to find the force (F) between the charges. The formula is F = k * |q1 * q2| / r^2.
Step 4: Substitute the values into the formula. k (Coulomb's constant) = 8.99 x 10^9 N m²/C², q1 = 1 x 10^-6 C, q2 = 1 x 10^-6 C, and r = 1 m.
Step 5: Calculate the numerator: |q1 * q2| = (1 x 10^-6 C) * (1 x 10^-6 C) = 1 x 10^-12 C².
Step 6: Calculate the denominator: r^2 = (1 m)² = 1 m².
Step 7: Now plug these values into the formula: F = (8.99 x 10^9 N m²/C²) * (1 x 10^-12 C²) / (1 m²).
Step 8: Perform the multiplication: F = 8.99 x 10^9 * 1 x 10^-12 = 8.99 N.
Step 9: The final answer is that the force between the two charges is 8.99 N.