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What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected i
What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected in series?
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Practice Questions
1 question
Q1
What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected in series?
2.4 µF
10 µF
1.5 µF
3.6 µF
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1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 => C_eq = 2.4 µF.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equivalent capacitance of two capacitors, 4 µF and 6 µF, connected in series?
Solution:
1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 => C_eq = 2.4 µF.
Steps: 8
Show Steps
Step 1: Identify the values of the capacitors. We have C1 = 4 µF and C2 = 6 µF.
Step 2: Use the formula for capacitors in series: 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values into the formula: 1/C_eq = 1/4 + 1/6.
Step 4: Find a common denominator for the fractions. The common denominator for 4 and 6 is 12.
Step 5: Rewrite the fractions: 1/4 = 3/12 and 1/6 = 2/12.
Step 6: Add the fractions: 1/C_eq = 3/12 + 2/12 = 5/12.
Step 7: Invert the fraction to find C_eq: C_eq = 12/5.
Step 8: Calculate 12/5 to get C_eq = 2.4 µF.
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