What is the potential difference across a 5 µF capacitor charged to 10 V?

What is the potential difference across a 5 µF capacitor charged to 10 V?

Correct Answer: 10 V

Step 1: Identify the values given in the question. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Use the formula for energy stored in a capacitor, which is U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula: U = 0.5 * (5 x 10^-6 F) * (10 V)^2.
Step 5: Calculate (10 V)^2, which is 100 V^2.
Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 100 V^2.
Step 7: Multiply 0.5 by 5 x 10^-6 F to get 2.5 x 10^-6 F.
Step 8: Now multiply 2.5 x 10^-6 F by 100 to get 0.00025 J.
Step 9: Convert 0.00025 J to a more readable form, which is 0.05 J.

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