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What is the potential difference across a 5 µF capacitor charged to 10 V?
What is the potential difference across a 5 µF capacitor charged to 10 V?
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Practice Questions
1 question
Q1
What is the potential difference across a 5 µF capacitor charged to 10 V?
50 mJ
0.05 J
0.5 J
5 J
Show Solution
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Energy stored in a capacitor, U = 0.5 * C * V^2 = 0.5 * (5 x 10^-6 F) * (10 V)^2 = 0.05 J.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the potential difference across a 5 µF capacitor charged to 10 V?
Solution:
Energy stored in a capacitor, U = 0.5 * C * V^2 = 0.5 * (5 x 10^-6 F) * (10 V)^2 = 0.05 J.
Steps: 9
Show Steps
Step 1: Identify the values given in the question. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Use the formula for energy stored in a capacitor, which is U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula: U = 0.5 * (5 x 10^-6 F) * (10 V)^2.
Step 5: Calculate (10 V)^2, which is 100 V^2.
Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 100 V^2.
Step 7: Multiply 0.5 by 5 x 10^-6 F to get 2.5 x 10^-6 F.
Step 8: Now multiply 2.5 x 10^-6 F by 100 to get 0.00025 J.
Step 9: Convert 0.00025 J to a more readable form, which is 0.05 J.
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