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What is the potential difference across a 5 µF capacitor charged to 10 V?

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Question: What is the potential difference across a 5 µF capacitor charged to 10 V?

Options:

  1. 50 mJ
  2. 0.05 J
  3. 0.5 J
  4. 5 J

Correct Answer: 0.05 J

Solution: 

Energy stored in a capacitor, U = 0.5 * C * V^2 = 0.5 * (5 x 10^-6 F) * (10 V)^2 = 0.05 J.

What is the potential difference across a 5 µF capacitor charged to 10 V?

Practice Questions

Q1
What is the potential difference across a 5 µF capacitor charged to 10 V?
  1. 50 mJ
  2. 0.05 J
  3. 0.5 J
  4. 5 J

Questions & Step-by-Step Solutions

What is the potential difference across a 5 µF capacitor charged to 10 V?
Correct Answer: 10 V
  • Step 1: Identify the values given in the question. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
  • Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
  • Step 3: Use the formula for energy stored in a capacitor, which is U = 0.5 * C * V^2.
  • Step 4: Substitute the values into the formula: U = 0.5 * (5 x 10^-6 F) * (10 V)^2.
  • Step 5: Calculate (10 V)^2, which is 100 V^2.
  • Step 6: Now substitute this value back into the equation: U = 0.5 * (5 x 10^-6 F) * 100 V^2.
  • Step 7: Multiply 0.5 by 5 x 10^-6 F to get 2.5 x 10^-6 F.
  • Step 8: Now multiply 2.5 x 10^-6 F by 100 to get 0.00025 J.
  • Step 9: Convert 0.00025 J to a more readable form, which is 0.05 J.
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