In a series where each term is the square of its position, what is the sum of the first 4 terms? (2023)
Practice Questions
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Q1
In a series where each term is the square of its position, what is the sum of the first 4 terms? (2023)
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The first four terms are 1^2, 2^2, 3^2, 4^2 which are 1, 4, 9, 16. Their sum is 1 + 4 + 9 + 16 = 30.
Questions & Step-by-step Solutions
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Q
Q: In a series where each term is the square of its position, what is the sum of the first 4 terms? (2023)
Solution: The first four terms are 1^2, 2^2, 3^2, 4^2 which are 1, 4, 9, 16. Their sum is 1 + 4 + 9 + 16 = 30.
Steps: 5
Step 1: Identify the position of each term. The first four positions are 1, 2, 3, and 4.
Step 2: Calculate the square of each position. For position 1, the square is 1^2 = 1. For position 2, the square is 2^2 = 4. For position 3, the square is 3^2 = 9. For position 4, the square is 4^2 = 16.
Step 3: List the squares you calculated: 1, 4, 9, and 16.
Step 4: Add the squares together: 1 + 4 + 9 + 16.
Step 5: Calculate the total sum: 1 + 4 = 5, then 5 + 9 = 14, and finally 14 + 16 = 30.
