A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?
Practice Questions
1 question
Q1
A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?
0.5
0.25
0.625
0.75
Total balls = 3 + 2 + 5 = 10. Probability of red or blue = (3 + 2) / 10 = 5 / 10 = 0.5.
Questions & Step-by-step Solutions
1 item
Q
Q: A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?
Solution: Total balls = 3 + 2 + 5 = 10. Probability of red or blue = (3 + 2) / 10 = 5 / 10 = 0.5.
Steps: 6
Step 1: Count the number of red balls in the box. There are 3 red balls.
Step 2: Count the number of blue balls in the box. There are 2 blue balls.
Step 3: Count the number of green balls in the box. There are 5 green balls.
Step 4: Add the total number of balls together: 3 red + 2 blue + 5 green = 10 total balls.
Step 5: Add the number of red and blue balls together: 3 red + 2 blue = 5 balls that are either red or blue.
Step 6: Calculate the probability of drawing a red or blue ball by dividing the number of red or blue balls by the total number of balls: 5 (red or blue) / 10 (total) = 0.5.
