A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random,

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Question: A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?

Options:

Correct Answer: 0.625

Solution:

Total balls = 3 + 2 + 5 = 10. Probability of red or blue = (3 + 2) / 10 = 5 / 10 = 0.5.

A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?

A box contains 3 red, 2 blue, and 5 green balls. If one ball is drawn at random, what is the probability that it is either red or blue?

Step 1: Count the number of red balls in the box. There are 3 red balls.
Step 2: Count the number of blue balls in the box. There are 2 blue balls.
Step 3: Count the number of green balls in the box. There are 5 green balls.
Step 4: Add the total number of balls together: 3 red + 2 blue + 5 green = 10 total balls.
Step 5: Add the number of red and blue balls together: 3 red + 2 blue = 5 balls that are either red or blue.
Step 6: Calculate the probability of drawing a red or blue ball by dividing the number of red or blue balls by the total number of balls: 5 (red or blue) / 10 (total) = 0.5.

Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and the number of favorable items in a probability scenario.