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What is the total capacitance of two capacitors of 4 µF and 6 µF in series?

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Question: What is the total capacitance of two capacitors of 4 µF and 6 µF in series?

Options:

  1. 2.4 µF
  2. 10 µF
  3. 1.5 µF
  4. 3.6 µF

Correct Answer: 2.4 µF

Solution: 

1/C_eq = 1/C1 + 1/C2 = 1/4 + 1/6 = 5/12, thus C_eq = 12/5 = 2.4 µF.

What is the total capacitance of two capacitors of 4 µF and 6 µF in series?

Practice Questions

Q1
What is the total capacitance of two capacitors of 4 µF and 6 µF in series?
  1. 2.4 µF
  2. 10 µF
  3. 1.5 µF
  4. 3.6 µF

Questions & Step-by-Step Solutions

What is the total capacitance of two capacitors of 4 µF and 6 µF in series?
Correct Answer: 2.4 µF
  • Step 1: Identify the values of the capacitors. We have C1 = 4 µF and C2 = 6 µF.
  • Step 2: Use the formula for total capacitance in series: 1/C_eq = 1/C1 + 1/C2.
  • Step 3: Substitute the values into the formula: 1/C_eq = 1/4 + 1/6.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 4 and 6 is 12.
  • Step 5: Rewrite the fractions: 1/4 = 3/12 and 1/6 = 2/12.
  • Step 6: Add the fractions: 1/C_eq = 3/12 + 2/12 = 5/12.
  • Step 7: To find C_eq, take the reciprocal: C_eq = 12/5.
  • Step 8: Calculate 12/5 to get the final answer: C_eq = 2.4 µF.
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