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What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in ser

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Question: What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in series?

Options:

  1. 10 Ω
  2. 8 Ω
  3. 5 Ω
  4. 3 Ω

Correct Answer: 10 Ω

Solution: 

R_eq = R1 + R2 + R3 = 2 Ω + 3 Ω + 5 Ω = 10 Ω.

What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in ser

Practice Questions

Q1
What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in series?
  1. 10 Ω
  2. 8 Ω
  3. 5 Ω
  4. 3 Ω

Questions & Step-by-Step Solutions

What is the equivalent resistance of three resistors of 2 Ω, 3 Ω, and 5 Ω in series?
Correct Answer: 10 Ω
  • Step 1: Identify the values of the resistors. We have three resistors: R1 = 2 Ω, R2 = 3 Ω, and R3 = 5 Ω.
  • Step 2: Use the formula for equivalent resistance in series, which is R_eq = R1 + R2 + R3.
  • Step 3: Substitute the values into the formula: R_eq = 2 Ω + 3 Ω + 5 Ω.
  • Step 4: Perform the addition: 2 + 3 = 5, then 5 + 5 = 10.
  • Step 5: Conclude that the equivalent resistance R_eq is 10 Ω.
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