If a capacitor of 10 µF is charged to 20 V, what is the energy stored in the capacitor?

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Q: If a capacitor of 10 µF is charged to 20 V, what is the energy stored in the capacitor?

Solution: Energy stored, U = 0.5 * C * V^2 = 0.5 * 10 x 10^-6 F * (20 V)^2 = 0.02 J.

Steps: 9

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 10 microfarads (µF) and a voltage (V) of 20 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 10 µF is equal to 10 x 10^-6 F.
Step 3: Write down the formula for the energy (U) stored in a capacitor: U = 0.5 * C * V^2.
Step 4: Substitute the values into the formula. Replace C with 10 x 10^-6 F and V with 20 V: U = 0.5 * (10 x 10^-6) * (20)^2.
Step 5: Calculate (20)^2, which is 400.
Step 6: Now substitute this value back into the equation: U = 0.5 * (10 x 10^-6) * 400.
Step 7: Multiply 0.5 by 400 to get 200.
Step 8: Now multiply 200 by 10 x 10^-6: 200 * 10 x 10^-6 = 0.02 J.
Step 9: Conclude that the energy stored in the capacitor is 0.02 joules.