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What is the capacitance of a capacitor with a charge of 6 µC and a voltage of 12

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Question: What is the capacitance of a capacitor with a charge of 6 µC and a voltage of 12 V?

Options:

  1. 0.5 µF
  2. 0.25 µF
  3. 0.75 µF
  4. 1 µF

Correct Answer: 0.5 µF

Solution: 

C = Q/V = 6 x 10^-6 C / 12 V = 0.5 x 10^-6 F = 0.5 µF.

What is the capacitance of a capacitor with a charge of 6 µC and a voltage of 12

Practice Questions

Q1
What is the capacitance of a capacitor with a charge of 6 µC and a voltage of 12 V?
  1. 0.5 µF
  2. 0.25 µF
  3. 0.75 µF
  4. 1 µF

Questions & Step-by-Step Solutions

What is the capacitance of a capacitor with a charge of 6 µC and a voltage of 12 V?
Correct Answer: 0.5 µF
  • Step 1: Identify the formula for capacitance, which is C = Q / V.
  • Step 2: Note the values given in the question: charge (Q) is 6 µC and voltage (V) is 12 V.
  • Step 3: Convert the charge from microcoulombs to coulombs: 6 µC = 6 x 10^-6 C.
  • Step 4: Substitute the values into the formula: C = (6 x 10^-6 C) / (12 V).
  • Step 5: Perform the division: C = 0.5 x 10^-6 F.
  • Step 6: Convert the result back to microfarads: 0.5 x 10^-6 F = 0.5 µF.
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