What is the electric field strength at a distance of 2 m from a point charge of +5 µC?
Practice Questions
1 question
Q1
What is the electric field strength at a distance of 2 m from a point charge of +5 µC?
1.12 N/C
0.56 N/C
2.25 N/C
0.75 N/C
E = k * |q| / r^2 = (8.99 x 10^9 N m²/C²) * (5 x 10^-6 C) / (2 m)^2 = 1.12 N/C.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the electric field strength at a distance of 2 m from a point charge of +5 µC?
Solution: E = k * |q| / r^2 = (8.99 x 10^9 N m²/C²) * (5 x 10^-6 C) / (2 m)^2 = 1.12 N/C.
Steps: 7
Step 1: Identify the formula for electric field strength (E) due to a point charge: E = k * |q| / r^2.
Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 8.99 x 10^9 N m²/C², q (the charge) = +5 µC = 5 x 10^-6 C, and r (the distance) = 2 m.
Step 3: Substitute the values into the formula: E = (8.99 x 10^9 N m²/C²) * (5 x 10^-6 C) / (2 m)^2.
Step 4: Calculate (2 m)^2, which is 4 m².
Step 5: Now calculate E: E = (8.99 x 10^9) * (5 x 10^-6) / 4.
Step 6: Perform the multiplication: (8.99 x 10^9) * (5 x 10^-6) = 44.95 x 10^3 N/C.
Step 7: Finally, divide by 4: E = 44.95 x 10^3 N/C / 4 = 11.2375 x 10^3 N/C = 1.12 N/C.
