A store offers a 30% discount on a jacket that is originally priced at $200. If

What’s inside this PDF?

Question: A store offers a 30% discount on a jacket that is originally priced at $200. If the store then applies an additional 10% discount on the already discounted price, what is the final selling price? (2023)

Options:

$140
$150
$160
$170

Correct Answer: $140

Exam Year: 2023

Solution:

First discount: $200 - (30% of $200) = $200 - $60 = $140. Second discount: $140 - (10% of $140) = $140 - $14 = $126.

Practice Questions

Q1

A store offers a 30% discount on a jacket that is originally priced at $200. If the store then applies an additional 10% discount on the already discounted price, what is the final selling price? (2023)

$140
$150
$160
$170

Questions & Step-by-Step Solutions

A store offers a 30% discount on a jacket that is originally priced at $200. If the store then applies an additional 10% discount on the already discounted price, what is the final selling price? (2023)

Step 1: Calculate the first discount amount. The original price of the jacket is $200. The first discount is 30% of $200.
Step 2: Calculate 30% of $200. 30% of $200 is $60.
Step 3: Subtract the first discount from the original price. $200 - $60 = $140. This is the new price after the first discount.
Step 4: Calculate the second discount amount. The second discount is 10% of the new price, which is $140.
Step 5: Calculate 10% of $140. 10% of $140 is $14.
Step 6: Subtract the second discount from the new price. $140 - $14 = $126. This is the final selling price of the jacket.

Percentage Calculation – Understanding how to calculate percentages and apply them sequentially to find discounts.
Sequential Discounts – Applying multiple discounts in succession rather than calculating a single discount on the original price.

A store offers a 30% discount on a jacket that is originally priced at $200. If

What’s inside this PDF?

A store offers a 30% discount on a jacket that is originally priced at $200. If

Practice Questions

Questions & Step-by-Step Solutions

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