What is the sum of the first 15 terms of an arithmetic progression where the fir

What is the sum of the first 15 terms of an arithmetic progression where the first term is 2 and the common difference is 4?

What is the sum of the first 15 terms of an arithmetic progression where the first term is 2 and the common difference is 4?

Step 1: Identify the first term (a) and the common difference (d) of the arithmetic progression. Here, a = 2 and d = 4.
Step 2: Determine the number of terms (n) you want to sum. In this case, n = 15.
Step 3: Use the formula for the sum of the first n terms of an arithmetic progression: S_n = n/2 * (2a + (n-1)d).
Step 4: Substitute the values into the formula: S_15 = 15/2 * (2*2 + (15-1)*4).
Step 5: Calculate 2*2, which equals 4.
Step 6: Calculate (15-1)*4, which equals 14*4 = 56.
Step 7: Add the results from Step 5 and Step 6: 4 + 56 = 60.
Step 8: Now substitute back into the formula: S_15 = 15/2 * 60.
Step 9: Calculate 15/2, which equals 7.5.
Step 10: Finally, multiply 7.5 by 60 to get the sum: 7.5 * 60 = 450.

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