If a ball is thrown vertically upward with an initial velocity of 15 m/s, how high will it go before coming to a stop?

1 question

1 item

Q: If a ball is thrown vertically upward with an initial velocity of 15 m/s, how high will it go before coming to a stop?

Solution: Using the formula h = v²/(2g), where v = 15 m/s and g = 9.81 m/s², we find h = (15)²/(2*9.81) ≈ 11.47 m.

Steps: 8

Step 1: Identify the initial velocity of the ball, which is given as 15 m/s.
Step 2: Identify the acceleration due to gravity, which is approximately 9.81 m/s² (this is the value we use when the ball is moving upward).
Step 3: Use the formula for maximum height, which is h = v² / (2g). Here, 'h' is the height, 'v' is the initial velocity, and 'g' is the acceleration due to gravity.
Step 4: Substitute the values into the formula: h = (15 m/s)² / (2 * 9.81 m/s²).
Step 5: Calculate (15 m/s)², which equals 225 m²/s².
Step 6: Calculate 2 * 9.81 m/s², which equals 19.62 m/s².
Step 7: Divide 225 m²/s² by 19.62 m/s² to find h: h ≈ 11.47 m.
Step 8: Conclude that the maximum height the ball will reach before coming to a stop is approximately 11.47 meters.