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A projectile is launched at an angle of 30 degrees with an initial velocity of 2

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Question: A projectile is launched at an angle of 30 degrees with an initial velocity of 20 m/s. What is the horizontal component of its velocity?

Options:

  1. 10 m/s
  2. 17.32 m/s
  3. 20 m/s
  4. 5 m/s

Correct Answer: 17.32 m/s

Solution: 

The horizontal component is given by v_x = v * cos(θ) = 20 * cos(30°) = 20 * (√3/2) ≈ 17.32 m/s.

A projectile is launched at an angle of 30 degrees with an initial velocity of 2

Practice Questions

Q1
A projectile is launched at an angle of 30 degrees with an initial velocity of 20 m/s. What is the horizontal component of its velocity?
  1. 10 m/s
  2. 17.32 m/s
  3. 20 m/s
  4. 5 m/s

Questions & Step-by-Step Solutions

A projectile is launched at an angle of 30 degrees with an initial velocity of 20 m/s. What is the horizontal component of its velocity?
Correct Answer: 17.32 m/s
  • Step 1: Identify the initial velocity of the projectile, which is 20 m/s.
  • Step 2: Identify the angle of launch, which is 30 degrees.
  • Step 3: Use the formula for the horizontal component of velocity, which is v_x = v * cos(θ).
  • Step 4: Substitute the values into the formula: v_x = 20 * cos(30°).
  • Step 5: Calculate cos(30°). The value of cos(30°) is √3/2.
  • Step 6: Substitute cos(30°) into the equation: v_x = 20 * (√3/2).
  • Step 7: Calculate the result: v_x = 20 * (√3/2) ≈ 17.32 m/s.
  • Projectile Motion – Understanding the components of velocity in projectile motion, specifically how to calculate the horizontal component using trigonometric functions.
  • Trigonometry in Physics – Applying cosine to find the horizontal component of velocity based on the launch angle.
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