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If a charge of +10 μC is placed in an electric field of strength 200 N/C, what i
If a charge of +10 μC is placed in an electric field of strength 200 N/C, what is the force experienced by the charge? (2019)
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Q1
If a charge of +10 μC is placed in an electric field of strength 200 N/C, what is the force experienced by the charge? (2019)
200 N
2 N
20 N
0.5 N
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Force F = qE = (10 × 10^-6 C) * (200 N/C) = 2 N.
Questions & Step-by-step Solutions
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Q
Q: If a charge of +10 μC is placed in an electric field of strength 200 N/C, what is the force experienced by the charge? (2019)
Solution:
Force F = qE = (10 × 10^-6 C) * (200 N/C) = 2 N.
Steps: 6
Show Steps
Step 1: Identify the charge value. The charge given is +10 μC (microcoulombs). Convert this to coulombs: +10 μC = 10 × 10^-6 C.
Step 2: Identify the electric field strength. The electric field strength given is 200 N/C.
Step 3: Use the formula for force in an electric field, which is F = qE, where F is the force, q is the charge, and E is the electric field strength.
Step 4: Substitute the values into the formula: F = (10 × 10^-6 C) * (200 N/C).
Step 5: Calculate the force: F = 10 × 200 × 10^-6 = 2000 × 10^-6 = 2 N.
Step 6: Conclude that the force experienced by the charge is 2 N.
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