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What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1

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Question: What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L atm/K mol) (2020)

Options:

  1. 2.06 atm
  2. 0.82 atm
  3. 1.01 atm
  4. 0.25 atm

Correct Answer: 2.06 atm

Exam Year: 2020

Solution: 

Osmotic pressure (π) = nRT/V = (0.1 mol)(0.0821 L atm/K mol)(298 K) = 2.06 atm.

What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1

Practice Questions

Q1
What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L atm/K mol) (2020)
  1. 2.06 atm
  2. 0.82 atm
  3. 1.01 atm
  4. 0.25 atm

Questions & Step-by-Step Solutions

What is the osmotic pressure of a solution containing 0.1 moles of glucose in 1 liter of solution at 25 °C? (R = 0.0821 L atm/K mol) (2020)
  • Step 1: Identify the formula for osmotic pressure, which is π = nRT/V.
  • Step 2: Determine the values needed for the formula: n (number of moles) = 0.1 moles, R (ideal gas constant) = 0.0821 L atm/K mol, T (temperature in Kelvin) = 25 °C + 273 = 298 K, and V (volume in liters) = 1 liter.
  • Step 3: Plug the values into the formula: π = (0.1 mol)(0.0821 L atm/K mol)(298 K) / (1 L).
  • Step 4: Calculate the result: π = (0.1)(0.0821)(298) = 2.06 atm.
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