Question: If 0.5 moles of a non-volatile solute are dissolved in 1 kg of water, what is the expected change in boiling point? (Kb for water = 0.52 °C kg/mol) (2021)

Options:

1. 0.26 °C
2. 0.52 °C
3. 1.04 °C
4. 0.78 °C

Correct Answer: 1.04 °C

Exam Year: 2021

Solution:

Boiling point elevation = i * Kb * m = 1 * 0.52 * 0.5 = 0.26 °C, so change = 0.52 °C.