What is the value of x in the polynomial equation 3x^2 + 12x = 0?
Practice Questions
1 question
Q1
What is the value of x in the polynomial equation 3x^2 + 12x = 0?
x = 0, -4
x = 0, 4
x = -3, -4
x = 3, 4
Step 1: Factor out 3x: 3x(x + 4) = 0. Step 2: Set each factor to zero: 3x = 0 or x + 4 = 0. Step 3: Solutions are x = 0 and x = -4.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the value of x in the polynomial equation 3x^2 + 12x = 0?
Solution: Step 1: Factor out 3x: 3x(x + 4) = 0. Step 2: Set each factor to zero: 3x = 0 or x + 4 = 0. Step 3: Solutions are x = 0 and x = -4.
Steps: 4
Step 1: Look at the equation 3x^2 + 12x = 0. We want to make it easier to solve by factoring. First, we notice that both terms have a common factor of 3x. So, we factor that out: 3x(x + 4) = 0.
Step 2: Now we have a product of two factors equal to zero. For this to be true, at least one of the factors must be zero. So, we set each factor to zero: 3x = 0 or x + 4 = 0.
Step 3: Solve each equation. For 3x = 0, divide both sides by 3 to get x = 0. For x + 4 = 0, subtract 4 from both sides to get x = -4.
Step 4: The solutions to the equation are x = 0 and x = -4.
