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What is the value of x in the polynomial equation 3x^2 + 12x = 0?

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Question: What is the value of x in the polynomial equation 3x^2 + 12x = 0?

Options:

  1. x = 0, -4
  2. x = 0, 4
  3. x = -3, -4
  4. x = 3, 4

Correct Answer: x = 0, -4

Solution: 

Step 1: Factor out 3x: 3x(x + 4) = 0. Step 2: Set each factor to zero: 3x = 0 or x + 4 = 0. Step 3: Solutions are x = 0 and x = -4.

What is the value of x in the polynomial equation 3x^2 + 12x = 0?

Practice Questions

Q1
What is the value of x in the polynomial equation 3x^2 + 12x = 0?
  1. x = 0, -4
  2. x = 0, 4
  3. x = -3, -4
  4. x = 3, 4

Questions & Step-by-Step Solutions

What is the value of x in the polynomial equation 3x^2 + 12x = 0?
Correct Answer: x = 0 and x = -4
  • Step 1: Look at the equation 3x^2 + 12x = 0. We want to make it easier to solve by factoring. First, we notice that both terms have a common factor of 3x. So, we factor that out: 3x(x + 4) = 0.
  • Step 2: Now we have a product of two factors equal to zero. For this to be true, at least one of the factors must be zero. So, we set each factor to zero: 3x = 0 or x + 4 = 0.
  • Step 3: Solve each equation. For 3x = 0, divide both sides by 3 to get x = 0. For x + 4 = 0, subtract 4 from both sides to get x = -4.
  • Step 4: The solutions to the equation are x = 0 and x = -4.
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