Question: What is the work done on a gas when it is compressed from 4 L to 2 L at a constant pressure of 2 atm?
Options:
Correct Answer: 4 L·atm
Solution:
Work done (W) = P * ΔV = 2 atm * (2 L - 4 L) = 2 atm * (-2 L) = -4 L·atm (work done on the gas is positive).