A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorb

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Question: A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorbed if the latent heat of fusion of ice is 334,000 J/kg?

Options:

Correct Answer: 668,000 J

Solution:

Heat absorbed = mass * latent heat = 2 kg * 334,000 J/kg = 668,000 J.

A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorbed if the latent heat of fusion of ice is 334,000 J/kg?

A 2 kg block of ice at 0°C is converted to water at 0°C. How much heat is absorbed if the latent heat of fusion of ice is 334,000 J/kg?

Step 1: Identify the mass of the ice block. In this case, it is 2 kg.
Step 2: Identify the latent heat of fusion of ice. It is given as 334,000 J/kg.
Step 3: Use the formula for heat absorbed, which is: Heat absorbed = mass * latent heat.
Step 4: Substitute the values into the formula: Heat absorbed = 2 kg * 334,000 J/kg.
Step 5: Calculate the result: 2 * 334,000 = 668,000 J.
Step 6: Conclude that the heat absorbed when the ice is converted to water is 668,000 J.

Latent Heat of Fusion – The amount of heat required to convert a unit mass of a solid into a liquid without a change in temperature.
Heat Transfer – The process of energy moving from one system to another, in this case, from ice to water.
Mass and Energy Relationship – Understanding how mass and specific latent heat relate to the total energy absorbed or released during phase changes.