If 500 J of heat is added to a system and 200 J of work is done by the system, w
Practice Questions
Q1
If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy of the system?
300 J
500 J
700 J
200 J
Questions & Step-by-Step Solutions
If 500 J of heat is added to a system and 200 J of work is done by the system, what is the change in internal energy of the system?
Step 1: Identify the amount of heat added to the system, which is 500 J. This is represented as Q.
Step 2: Identify the amount of work done by the system, which is 200 J. This is represented as W.
Step 3: Recall the formula from the first law of thermodynamics: ΔU = Q - W.
Step 4: Substitute the values into the formula: ΔU = 500 J - 200 J.
Step 5: Perform the subtraction: 500 J - 200 J = 300 J.
Step 6: Conclude that the change in internal energy (ΔU) of the system is 300 J.
First Law of Thermodynamics – The principle that the change in internal energy of a system (ΔU) is equal to the heat added to the system (Q) minus the work done by the system (W).
