What is the determinant of J = [[5, 4], [2, 3]]? (2022)

₹0.0

Question: What is the determinant of J = [[5, 4], [2, 3]]? (2022)

Options:

Correct Answer: 7

Exam Year: 2022

Solution:

The determinant of J is (5*3) - (4*2) = 15 - 8 = 7.

What is the determinant of J = [[5, 4], [2, 3]]? (2022)

What is the determinant of J = [[5, 4], [2, 3]]? (2022)

Step 1: Identify the matrix J, which is [[5, 4], [2, 3]].
Step 2: Write down the formula for the determinant of a 2x2 matrix, which is (a*d) - (b*c).
Step 3: Assign the values from the matrix to the variables: a = 5, b = 4, c = 2, d = 3.
Step 4: Calculate a*d, which is 5*3 = 15.
Step 5: Calculate b*c, which is 4*2 = 8.
Step 6: Subtract the result of b*c from a*d: 15 - 8 = 7.
Step 7: Conclude that the determinant of J is 7.

No concepts available.