Question: A tuning fork vibrates at a frequency of 440 Hz. What is the time period of its vibration? (2020)
Options:
0.00227 s
0.0045 s
0.01 s
0.005 s
Correct Answer: 0.00227 s
Exam Year: 2020
Solution:
Time period (T) = 1 / frequency = 1 / 440 Hz ≈ 0.00227 s
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of its
Practice Questions
Q1
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of its vibration? (2020)
0.00227 s
0.0045 s
0.01 s
0.005 s
Questions & Step-by-Step Solutions
A tuning fork vibrates at a frequency of 440 Hz. What is the time period of its vibration? (2020)
Step 1: Understand that frequency (f) is how many times something happens in one second. In this case, the tuning fork vibrates 440 times in one second.
Step 2: The time period (T) is the time it takes for one complete vibration. It is the opposite of frequency.
Step 3: Use the formula for time period: T = 1 / f.
Step 4: Substitute the frequency into the formula: T = 1 / 440 Hz.
Step 5: Calculate the time period: T = 1 / 440, which is approximately 0.00227 seconds.
Frequency and Time Period – The relationship between frequency and time period is given by the formula T = 1/f, where T is the time period and f is the frequency.
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