A spring is compressed by 0.2 m and has a spring constant of 500 N/m. What is th

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Question: A spring is compressed by 0.2 m and has a spring constant of 500 N/m. What is the potential energy stored in the spring? (2023)

Options:

Correct Answer: 10 J

Exam Year: 2023

Solution:

Potential Energy in Spring (PE) = 1/2 kx^2 = 1/2 * 500 N/m * (0.2 m)^2 = 10 J

A spring is compressed by 0.2 m and has a spring constant of 500 N/m. What is the potential energy stored in the spring? (2023)

A spring is compressed by 0.2 m and has a spring constant of 500 N/m. What is the potential energy stored in the spring? (2023)

Step 1: Identify the formula for potential energy stored in a spring, which is PE = 1/2 kx^2.
Step 2: Identify the values needed for the formula: the spring constant (k) is 500 N/m and the compression distance (x) is 0.2 m.
Step 3: Substitute the values into the formula: PE = 1/2 * 500 N/m * (0.2 m)^2.
Step 4: Calculate (0.2 m)^2, which equals 0.04 m^2.
Step 5: Multiply 500 N/m by 0.04 m^2, which equals 20 N*m.
Step 6: Divide 20 N*m by 2, which equals 10 J.
Step 7: Conclude that the potential energy stored in the spring is 10 Joules.

Potential Energy in Springs – The potential energy stored in a compressed or stretched spring is calculated using the formula PE = 1/2 kx^2, where k is the spring constant and x is the displacement from the equilibrium position.