What is the peak voltage of an AC source if its RMS voltage is 220 V? (2021)

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311 V
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Q: What is the peak voltage of an AC source if its RMS voltage is 220 V? (2021)

Solution: The peak voltage (V_peak) is related to the RMS voltage (V_rms) by the formula V_peak = V_rms × √2. Therefore, V_peak = 220 V × √2 ≈ 311 V.

Steps: 7

Step 1: Understand that RMS voltage (V_rms) is a way to express the effective voltage of an AC source.
Step 2: Know that the peak voltage (V_peak) is the maximum voltage that the AC source reaches.
Step 3: Remember the formula that relates peak voltage to RMS voltage: V_peak = V_rms × √2.
Step 4: Substitute the given RMS voltage (220 V) into the formula: V_peak = 220 V × √2.
Step 5: Calculate √2, which is approximately 1.414.
Step 6: Multiply 220 V by 1.414 to find the peak voltage: V_peak ≈ 220 V × 1.414.
Step 7: Perform the multiplication: V_peak ≈ 311 V.

What is the peak voltage of an AC source if its RMS voltage is 220 V? (2021)

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