Two capacitors of capacitance 2μF and 3μF are connected in series. What is the e

Practice Questions

Q1
Two capacitors of capacitance 2μF and 3μF are connected in series. What is the equivalent capacitance? (2019)
  1. 1.2μF
  2. 1.5μF
  3. 0.86μF
  4. 5μF

Questions & Step-by-Step Solutions

Two capacitors of capacitance 2μF and 3μF are connected in series. What is the equivalent capacitance? (2019)
  • Step 1: Identify the capacitance values of the capacitors. We have C1 = 2μF and C2 = 3μF.
  • Step 2: Use the formula for capacitors in series, which is 1/C_eq = 1/C1 + 1/C2.
  • Step 3: Substitute the values into the formula: 1/C_eq = 1/2 + 1/3.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 2 and 3 is 6.
  • Step 5: Rewrite the fractions: 1/2 = 3/6 and 1/3 = 2/6.
  • Step 6: Add the fractions: 1/C_eq = 3/6 + 2/6 = 5/6.
  • Step 7: To find C_eq, take the reciprocal of 5/6: C_eq = 6/5.
  • Step 8: Convert 6/5 to a decimal or a microfarad value: C_eq = 1.2μF.
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