Two capacitors of capacitance 2μF and 3μF are connected in series. What is the e

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Question: Two capacitors of capacitance 2μF and 3μF are connected in series. What is the equivalent capacitance? (2019)

Options:

Correct Answer: 0.86μF

Exam Year: 2019

Solution:

For capacitors in series, 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/2 + 1/3 = 5/6, giving C_eq = 6/5 = 1.2μF.

Two capacitors of capacitance 2μF and 3μF are connected in series. What is the equivalent capacitance? (2019)

Two capacitors of capacitance 2μF and 3μF are connected in series. What is the equivalent capacitance? (2019)

Step 1: Identify the capacitance values of the capacitors. We have C1 = 2μF and C2 = 3μF.
Step 2: Use the formula for capacitors in series, which is 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values into the formula: 1/C_eq = 1/2 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 2 and 3 is 6.
Step 5: Rewrite the fractions: 1/2 = 3/6 and 1/3 = 2/6.
Step 6: Add the fractions: 1/C_eq = 3/6 + 2/6 = 5/6.
Step 7: To find C_eq, take the reciprocal of 5/6: C_eq = 6/5.
Step 8: Convert 6/5 to a decimal or a microfarad value: C_eq = 1.2μF.

Capacitance in Series – The equivalent capacitance of capacitors connected in series is found using the formula 1/C_eq = 1/C1 + 1/C2.