What is the equivalent resistance of two resistors of 8Ω and 4Ω connected in ser

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Question: What is the equivalent resistance of two resistors of 8Ω and 4Ω connected in series? (2022)

Options:

Correct Answer: 12Ω

Exam Year: 2022

Solution:

In series, R_eq = R1 + R2 = 8Ω + 4Ω = 12Ω.

What is the equivalent resistance of two resistors of 8Ω and 4Ω connected in series? (2022)

What is the equivalent resistance of two resistors of 8Ω and 4Ω connected in series? (2022)

Step 1: Identify the resistors. We have two resistors: one is 8Ω and the other is 4Ω.
Step 2: Understand that when resistors are connected in series, you add their resistances together.
Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_eq = 8Ω + 4Ω.
Step 5: Perform the addition: 8Ω + 4Ω = 12Ω.
Step 6: Conclude that the equivalent resistance of the two resistors in series is 12Ω.

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