What is the total current in a circuit with a 9V battery and two 3Ω resistors in

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Question: What is the total current in a circuit with a 9V battery and two 3Ω resistors in series? (2021)

Options:

Correct Answer: 1A

Exam Year: 2021

Solution:

Total resistance R = 3Ω + 3Ω = 6Ω. Current I = V/R = 9V/6Ω = 1.5A.

What is the total current in a circuit with a 9V battery and two 3Ω resistors in series? (2021)

What is the total current in a circuit with a 9V battery and two 3Ω resistors in series? (2021)

Step 1: Identify the voltage of the battery. In this case, it is 9V.
Step 2: Identify the resistance of each resistor. Each resistor has a resistance of 3Ω.
Step 3: Since the resistors are in series, add their resistances together. 3Ω + 3Ω = 6Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 9V / 6Ω.
Step 6: Calculate the current: 9V divided by 6Ω equals 1.5A.

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