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What is the osmotic pressure of a solution containing 2 moles of glucose in 1 li
What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (2021)
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Q1
What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (2021)
0.0821 atm
1.0 atm
2.0 atm
4.0 atm
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Osmotic pressure (π) = iCRT = 1 * 2 * 0.0821 * 298 = 4.0 atm (i = 1 for glucose).
Questions & Step-by-step Solutions
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Q
Q: What is the osmotic pressure of a solution containing 2 moles of glucose in 1 liter of solution at 25 °C? (2021)
Solution:
Osmotic pressure (π) = iCRT = 1 * 2 * 0.0821 * 298 = 4.0 atm (i = 1 for glucose).
Steps: 7
Show Steps
Step 1: Identify the formula for osmotic pressure, which is π = iCRT.
Step 2: Determine the value of 'i' for glucose. Since glucose does not dissociate in solution, i = 1.
Step 3: Identify the number of moles of glucose in the solution. Here, there are 2 moles of glucose.
Step 4: Identify the value of 'R', the ideal gas constant, which is 0.0821 L·atm/(K·mol).
Step 5: Convert the temperature from Celsius to Kelvin. 25 °C = 25 + 273 = 298 K.
Step 6: Plug the values into the osmotic pressure formula: π = 1 * 2 * 0.0821 * 298.
Step 7: Calculate the osmotic pressure: π = 1 * 2 * 0.0821 * 298 = 4.0 atm.
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