If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, what is the expected vapor pressure lowering? (2020)

Practice Questions

1 question
Q1
If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, what is the expected vapor pressure lowering? (2020)
  1. 0.5 P0
  2. 0.25 P0
  3. 0.75 P0
  4. 0.1 P0

Questions & Step-by-step Solutions

1 item
Q
Q: If 0.5 moles of a non-volatile solute is dissolved in 1 kg of water, what is the expected vapor pressure lowering? (2020)
Solution: Vapor pressure lowering = (moles of solute / moles of solvent) * P0 = (0.5 / 55.5) * P0 ≈ 0.25 P0.
Steps: 0

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