What is the freezing point depression of a solution containing 1 mole of NaCl in

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Question: What is the freezing point depression of a solution containing 1 mole of NaCl in 1 kg of water? (2022)

Options:

Correct Answer: 1.86 °C

Exam Year: 2022

Solution:

Freezing point depression = i * Kf * m = 2 * 1.86 * 1 = 3.72 °C (i = 2 for NaCl).

What is the freezing point depression of a solution containing 1 mole of NaCl in 1 kg of water? (2022)

What is the freezing point depression of a solution containing 1 mole of NaCl in 1 kg of water? (2022)

Step 1: Identify the formula for freezing point depression, which is ΔTf = i * Kf * m.
Step 2: Determine the value of 'i' for NaCl. Since NaCl dissociates into 2 ions (Na+ and Cl-), i = 2.
Step 3: Find the value of Kf for water. The Kf for water is 1.86 °C kg/mol.
Step 4: Calculate the molality (m) of the solution. Since we have 1 mole of NaCl in 1 kg of water, m = 1 mol/kg.
Step 5: Plug the values into the formula: ΔTf = 2 * 1.86 * 1.
Step 6: Perform the multiplication: 2 * 1.86 = 3.72 °C.
Step 7: Conclude that the freezing point depression of the solution is 3.72 °C.

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