Question: In a simple cubic lattice, how many atoms are present in one unit cell? (2019)
Options:
1
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8
Correct Answer: 1
Exam Year: 2019
Solution:
In a simple cubic lattice, there is 1 atom per unit cell (1/8 atom from each of the 8 corners).
In a simple cubic lattice, how many atoms are present in one unit cell? (2019)
Practice Questions
Q1
In a simple cubic lattice, how many atoms are present in one unit cell? (2019)
1
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8
Questions & Step-by-Step Solutions
In a simple cubic lattice, how many atoms are present in one unit cell? (2019)
Step 1: Understand what a simple cubic lattice is. It is a type of crystal structure where atoms are arranged in a cube shape.
Step 2: Identify the corners of the cube. A cube has 8 corners.
Step 3: Recognize that each corner of the cube has 1 atom, but this atom is shared with adjacent cubes.
Step 4: Since each corner atom is shared by 8 different cubes, only 1/8 of each corner atom belongs to one cube.
Step 5: Calculate the total contribution of atoms from the corners: 8 corners x 1/8 atom per corner = 1 atom.
Step 6: Conclude that there is a total of 1 atom in one unit cell of a simple cubic lattice.
Simple Cubic Lattice – A simple cubic lattice consists of atoms located at the corners of a cube, with each corner contributing 1/8 of an atom to the unit cell.
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