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For the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g), what is the expression for the equili

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Question: For the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g), what is the expression for the equilibrium constant Kp? (2020)

Options:

  1. (P_NH3)^2 / (P_N2)(P_H2)^3
  2. (P_N2)(P_H2)^3 / (P_NH3)^2
  3. (P_NH3)^2 (P_N2)(P_H2)^3
  4. (P_N2)(P_H2)^3 (P_NH3)^2

Correct Answer: (P_NH3)^2 / (P_N2)(P_H2)^3

Exam Year: 2020

Solution:

Kp is expressed in terms of the partial pressures of the gases involved in the reaction. For this reaction, Kp = (P_NH3)^2 / (P_N2)(P_H2)^3.

For the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g), what is the expression for the equili

Practice Questions

Q1
For the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g), what is the expression for the equilibrium constant Kp? (2020)
  1. (P_NH3)^2 / (P_N2)(P_H2)^3
  2. (P_N2)(P_H2)^3 / (P_NH3)^2
  3. (P_NH3)^2 (P_N2)(P_H2)^3
  4. (P_N2)(P_H2)^3 (P_NH3)^2

Questions & Step-by-Step Solutions

For the reaction N2(g) + 3H2(g) β‡Œ 2NH3(g), what is the expression for the equilibrium constant Kp? (2020)
  • Step 1: Identify the reaction: N2(g) + 3H2(g) β‡Œ 2NH3(g).
  • Step 2: Recognize that Kp is based on the partial pressures of the gases in the reaction.
  • Step 3: Write the products of the reaction in the numerator. Here, we have 2NH3, so we write (P_NH3)^2.
  • Step 4: Write the reactants of the reaction in the denominator. We have N2 and 3H2, so we write (P_N2) and (P_H2)^3 because there are 3 moles of H2.
  • Step 5: Combine the numerator and denominator to form the expression for Kp: Kp = (P_NH3)^2 / (P_N2)(P_H2)^3.
  • Equilibrium Constant Expression – Understanding how to derive the equilibrium constant expression (Kp) from a balanced chemical equation, specifically using partial pressures of gaseous reactants and products.
  • Stoichiometry in Reactions – Applying stoichiometric coefficients from the balanced equation to formulate the Kp expression correctly.
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