A 4 kg object is lifted to a height of 2 m. What is the work done against gravit
Practice Questions
Q1
A 4 kg object is lifted to a height of 2 m. What is the work done against gravity? (2022)
40 J
80 J
20 J
60 J
Questions & Step-by-Step Solutions
A 4 kg object is lifted to a height of 2 m. What is the work done against gravity? (2022)
Step 1: Identify the mass of the object. In this case, the mass is 4 kg.
Step 2: Identify the height to which the object is lifted. Here, the height is 2 m.
Step 3: Know the acceleration due to gravity (g). It is approximately 10 m/s².
Step 4: Use the formula for work done against gravity: Work done = mass × g × height.
Step 5: Substitute the values into the formula: Work done = 4 kg × 10 m/s² × 2 m.
Step 6: Calculate the result: 4 × 10 = 40, then 40 × 2 = 80.
Step 7: Conclude that the work done against gravity is 80 Joules.
Work Done Against Gravity – Work is calculated as the product of mass, gravitational acceleration, and height. It measures the energy required to lift an object against the force of gravity.
