A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the

A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)

A 1 kg ball is thrown vertically upwards with a velocity of 20 m/s. What is the maximum height it reaches? (g = 10 m/s²) (2021)

Step 1: Identify the initial velocity (v) of the ball, which is 20 m/s.
Step 2: Identify the acceleration due to gravity (g), which is 10 m/s².
Step 3: Use the formula for maximum height (h) reached by an object thrown upwards: h = v² / (2g).
Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 × 10 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 × 10 m/s², which equals 20 m/s².
Step 7: Divide 400 m²/s² by 20 m/s² to find h: 400 m²/s² / 20 m/s² = 20 m.
Step 8: Conclude that the maximum height reached by the ball is 20 meters.

Kinematics – The question tests the understanding of kinematic equations, specifically the relationship between initial velocity, acceleration due to gravity, and maximum height in vertical motion.
Energy Conservation – It also touches on the concept of energy conservation, where kinetic energy is converted to potential energy at the maximum height.