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A 5 kg block of ice at 0°C is converted to water at 0°C. If the latent heat of f
A 5 kg block of ice at 0°C is converted to water at 0°C. If the latent heat of fusion of ice is 334 kJ/kg, how much heat is absorbed?
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Practice Questions
1 question
Q1
A 5 kg block of ice at 0°C is converted to water at 0°C. If the latent heat of fusion of ice is 334 kJ/kg, how much heat is absorbed?
1670 kJ
334 kJ
167 kJ
3340 kJ
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Heat absorbed (Q) = m * Lf = 5 kg * 334 kJ/kg = 1670 kJ.
Questions & Step-by-step Solutions
1 item
Q
Q: A 5 kg block of ice at 0°C is converted to water at 0°C. If the latent heat of fusion of ice is 334 kJ/kg, how much heat is absorbed?
Solution:
Heat absorbed (Q) = m * Lf = 5 kg * 334 kJ/kg = 1670 kJ.
Steps: 5
Show Steps
Step 1: Identify the mass of the ice block. In this case, it is 5 kg.
Step 2: Identify the latent heat of fusion of ice. It is given as 334 kJ/kg.
Step 3: Use the formula for heat absorbed, which is Q = m * Lf, where Q is the heat absorbed, m is the mass, and Lf is the latent heat of fusion.
Step 4: Substitute the values into the formula: Q = 5 kg * 334 kJ/kg.
Step 5: Calculate the result: Q = 1670 kJ.
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