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In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated b

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Question: In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)

Options:

  1. 3W
  2. 9W
  3. 6W
  4. 12W

Correct Answer: 9W

Exam Year: 2021

Solution: 

Power is given by P = V²/R = (9V)² / 3Ω = 81V² / 3Ω = 27W.

In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated b

Practice Questions

Q1
In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
  1. 3W
  2. 9W
  3. 6W
  4. 12W

Questions & Step-by-Step Solutions

In a circuit with a 9V battery and a 3Ω resistor, what is the power dissipated by the resistor? (2021)
  • Step 1: Identify the values given in the problem. We have a voltage (V) of 9 volts and a resistance (R) of 3 ohms.
  • Step 2: Recall the formula for power (P) in a resistor, which is P = V² / R.
  • Step 3: Substitute the values into the formula. Replace V with 9V and R with 3Ω: P = (9V)² / 3Ω.
  • Step 4: Calculate (9V)², which is 81V².
  • Step 5: Now divide 81V² by 3Ω: 81V² / 3Ω = 27W.
  • Step 6: Conclude that the power dissipated by the resistor is 27 watts.
  • Ohm's Law and Power Calculation – Understanding the relationship between voltage, resistance, and power in electrical circuits.
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