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A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the m
A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches?
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A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches?
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Using the formula h = v²/(2g), where v = 20 m/s and g = 9.8 m/s², h = (20)²/(2 * 9.8) ≈ 20.4 m, which rounds to 20 m.
Questions & Step-by-step Solutions
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Q: A 0.5 kg ball is thrown vertically upwards with a speed of 20 m/s. What is the maximum height it reaches?
Solution:
Using the formula h = v²/(2g), where v = 20 m/s and g = 9.8 m/s², h = (20)²/(2 * 9.8) ≈ 20.4 m, which rounds to 20 m.
Steps: 9
Show Steps
Step 1: Identify the initial speed (v) of the ball, which is given as 20 m/s.
Step 2: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 3: Use the formula for maximum height (h) reached by the ball: h = v² / (2g).
Step 4: Substitute the values into the formula: h = (20 m/s)² / (2 * 9.8 m/s²).
Step 5: Calculate (20 m/s)², which equals 400 m²/s².
Step 6: Calculate 2 * 9.8 m/s², which equals 19.6 m/s².
Step 7: Divide 400 m²/s² by 19.6 m/s² to find h: h = 400 / 19.6.
Step 8: Perform the division: h ≈ 20.408 m.
Step 9: Round the result to the nearest whole number, which is approximately 20 m.
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