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In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing th
In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
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In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
3A
2A
1A
4A
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Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Questions & Step-by-step Solutions
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Q
Q: In a circuit with a 9V battery and a 3Ω resistor, what is the current flowing through the resistor? (2023)
Solution:
Using Ohm's law, I = V/R = 9V / 3Ω = 3A.
Steps: 6
Show Steps
Step 1: Identify the voltage of the battery, which is 9 volts (V).
Step 2: Identify the resistance of the resistor, which is 3 ohms (Ω).
Step 3: Use Ohm's law formula, which is I = V / R, where I is the current, V is the voltage, and R is the resistance.
Step 4: Plug in the values into the formula: I = 9V / 3Ω.
Step 5: Calculate the current: 9 divided by 3 equals 3.
Step 6: Conclude that the current flowing through the resistor is 3 amperes (A).
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