What is the total resistance in a series circuit with resistors of 2Ω, 3Ω, and 5

₹0.0

Question: What is the total resistance in a series circuit with resistors of 2Ω, 3Ω, and 5Ω?

Options:

Correct Answer: 10Ω

Solution:

In a series circuit, total resistance (R_total) is the sum of individual resistances: R_total = R1 + R2 + R3 = 2Ω + 3Ω + 5Ω = 10Ω.

What is the total resistance in a series circuit with resistors of 2Ω, 3Ω, and 5Ω?

What is the total resistance in a series circuit with resistors of 2Ω, 3Ω, and 5Ω?

Step 1: Identify the resistors in the series circuit. We have three resistors: 2Ω, 3Ω, and 5Ω.
Step 2: Write down the formula for total resistance in a series circuit. The formula is R_total = R1 + R2 + R3.
Step 3: Substitute the values of the resistors into the formula. This means R_total = 2Ω + 3Ω + 5Ω.
Step 4: Add the values together. First, add 2Ω and 3Ω to get 5Ω. Then, add that result to 5Ω to get 10Ω.
Step 5: Conclude that the total resistance in the series circuit is 10Ω.

No concepts available.