A block of mass 2 kg is placed on a frictionless surface and is pushed with a fo

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Question: A block of mass 2 kg is placed on a frictionless surface and is pushed with a force of 10 N. What is its acceleration?

Options:

Correct Answer: 5 m/s²

Solution:

Using Newton\'s second law, F = ma. Here, F = 10 N and m = 2 kg. Therefore, a = F/m = 10/2 = 5 m/s².

A block of mass 2 kg is placed on a frictionless surface and is pushed with a force of 10 N. What is its acceleration?

A block of mass 2 kg is placed on a frictionless surface and is pushed with a force of 10 N. What is its acceleration?

Correct Answer: 5 m/s²

Step 1: Identify the mass of the block. The mass (m) is given as 2 kg.
Step 2: Identify the force applied to the block. The force (F) is given as 10 N.
Step 3: Recall Newton's second law of motion, which states that Force (F) equals mass (m) times acceleration (a). This can be written as F = ma.
Step 4: Rearrange the formula to solve for acceleration (a). This gives us a = F/m.
Step 5: Substitute the values of F and m into the formula. So, a = 10 N / 2 kg.
Step 6: Perform the division. 10 divided by 2 equals 5.
Step 7: State the final result. The acceleration (a) of the block is 5 m/s².

Newton's Second Law – The relationship between force, mass, and acceleration, expressed as F = ma.