Find the equation of the line that passes through the point (4, -1) and is perpendicular to the line y = 3x + 2.
Practice Questions
1 question
Q1
Find the equation of the line that passes through the point (4, -1) and is perpendicular to the line y = 3x + 2.
y = -1/3x + 5/3
y = 3x - 13
y = -3x + 11
y = 1/3x - 5/3
The slope of the given line is 3, so the slope of the perpendicular line is -1/3. Using point-slope form, we get y + 1 = -1/3(x - 4), which simplifies to y = -1/3x + 11/3.
Questions & Step-by-step Solutions
1 item
Q
Q: Find the equation of the line that passes through the point (4, -1) and is perpendicular to the line y = 3x + 2.
Solution: The slope of the given line is 3, so the slope of the perpendicular line is -1/3. Using point-slope form, we get y + 1 = -1/3(x - 4), which simplifies to y = -1/3x + 11/3.
